In the figure shown,the velocity of the lift | vedclass

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(C) Let the lift be moving upwards with velocity $\vec{v}_{L,g} = 2\,m/s \uparrow$.Block $A$ moves downwards relative to the lift with velocity $\vec{

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$4\,m/s \uparrow$

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(C) Let the lift be moving upwards with velocity $\vec{v}_{L,g} = 2\,m/s \uparrow$.Block $A$ moves downwards relative to the lift with velocity $\vec{v}_{A,L} = 2\,m/s \downarrow$.The string is winding on the motor shaft at $2\,m/s$,which means the string length on the side of block $A$ is decreasing at $2\,m/s$. Since the pulley is fixed to the lift,the velocity of block $B$ relative to the lift $(\vec{v}_{B,L})$ must be $2\,m/s$ upwards to maintain the string constraint.Now,we use the relative velocity formula: $\vec{v}_{B,g} = \vec{v}_{B,L} + \vec{v}_{L,g}$.Substituting the values: $\vec{v}_{B,g} = 2\,m/s \uparrow + 2\,m/s \uparrow = 4\,m/s \uparrow$.

In the figure shown,the velocity of the lift is $2\,m/s$ upwards. The string is winding on the motor shaft with a velocity of $2\,m/s$ and block $A$ is moving downwards with a velocity of $2\,m/s$ relative to the lift. Find the velocity of block $B$ with respect to the ground.

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