In the final answer of the expression frac{(2 | vedclass

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(B) Step $1$: Perform the subtraction in the numerator: $(29.2 - 20.2) = 9.0$. Since the numbers $29.2$ and $20.2$ have one decimal place,the result $

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$2$

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(B) Step $1$: Perform the subtraction in the numerator: $(29.2 - 20.2) = 9.0$. Since the numbers $29.2$ and $20.2$ have one decimal place,the result $9.0$ is limited to one decimal place,which gives it $2$ significant figures.Step $2$: The expression becomes $\frac{9.0 	imes 1.79 	imes 10^5}{1.37}$.Step $3$: In multiplication and division,the final result should have the same number of significant figures as the term with the least number of significant figures.Step $4$: The term $9.0$ has $2$ significant figures,$1.79$ has $3$ significant figures,and $1.37$ has $3$ significant figures.Step $5$: The least number of significant figures is $2$. Therefore,the final answer will have $2$ significant figures.

In the final answer of the expression $\frac{(29.2-20.2)(1.79 \times 10^5)}{1.37}$,the number of significant figures is:

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