In the following $p-V$ diagram, the equation of state along the curved path is given by $(V-2)^2 = 4aP$, where $a$ is a constant. The total work done in the closed path is:

$A$ thermodynamic system is taken from state $A$ to $B$ along $ACB$ and is brought back to $A$ along $BDA$ as shown in the $PV$ diagram. The net work done during the complete cycle is given by the area

$A$ thermodynamic system is taken from an original state $A$ to an intermediate state $B$ by a linear process as shown in the figure. Its volume is then reduced to the original value from $B$ to $C$ by an isobaric process. The total work done by the gas from $A$ to $B$ and $B$ to $C$ is: (in $J$)

The net work done by an ideal gas going through the cycle as shown in the $P-V$ diagram below is

The work done by a gas as it is taken in a cyclic process (shown in the graph) is (in $PV$)

$A$ sample of an ideal gas is taken through the cyclic process $abca$ as shown in the figure. The change in the internal energy of the gas along the path $ca$ is $-180\, J$. The gas absorbs $250\, J$ of heat along the path $ab$ and $60\, J$ along the path $bc$. The work done by the gas along the path $abc$ is ..... $J$.