In the following circuit,find the current through the path $ACB$ if each resistance $R = 4 \ \Omega$ and the battery voltage is $16 \ V$. (in $A$)

The electric current $i$ in the circuit shown is (in $\text{ A}$)

For the circuit shown,with $R_1 = 1.0\,\Omega$,$R_2 = 2.0\,\Omega$,$E_1 = 2\,V$ and $E_2 = E_3 = 4\,V$,the potential difference between the points $a$ and $b$ is approximately (in $V$):

Four resistors $A, B, C$ and $D$ form a Wheatstone bridge. The bridge is balanced when $C = 100 \ \Omega$. If $A$ and $B$ are interchanged,the bridge balances for $C = 121 \ \Omega$. The value of $D$ is: (in $\Omega$)

$A$ part of a circuit is shown in the figure. The ratio of the potential differences between the points $A$ and $C$,and the points $D$ and $E$ is

The heat generated in $1 \text{ minute}$ between points $A$ and $B$ in the given circuit, when a battery of $9 \text{ V}$ with internal resistance of $1 \ \Omega$ is connected across these points, is . . . . . . $J$.