In the following circuit,the current I_3 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the potential at the central node be $V$. Applying Kirchhoff's Current Law $(KCL)$ at the central node:$I_1 + I_2 = I_3$Using Ohm's law for ea

Vedclass · Accepted Answer

$-\frac{5}{6} \ A$

Vedclass · Answer

(D) Let the potential at the central node be $V$. Applying Kirchhoff's Current Law $(KCL)$ at the central node:$I_1 + I_2 = I_3$Using Ohm's law for each branch:$I_1 = \frac{8 - 6 - V}{28} = \frac{2 - V}{28}$$I_2 = \frac{12 - 6 - V}{54} = \frac{6 - V}{54}$$I_3 = \frac{V - 0}{0} = 	ext{undefined (this approach is complex)}$.Alternatively,using nodal analysis at the central node:$\frac{V - 8}{28} + \frac{V - 12}{54} + \frac{V - 6}{0} = 0$ is not correct. Let's use loop analysis.For loop $1$: $28 I_1 + 6 + 8 = 0 \implies 28 I_1 = -14 \implies I_1 = -0.5 \ A$.For loop $2$: $54 I_2 + 6 + 12 = 0 \implies 54 I_2 = -18 \implies I_2 = -1/3 \ A$.By $KCL$ at the junction: $I_3 = I_1 + I_2 = -0.5 + (-1/3) = -1/2 - 1/3 = -5/6 \ A$.

In the following circuit,the current $I_3$ is

Similar Questions

In the given Wheatstone bridge circuit,the current flowing through the $40 \Omega$ resistor is:

The current from the battery in the given circuit is ................ $A$.

Five resistances are connected as shown in the figure. The effective resistance between points $A$ and $B$ is

In the given circuit,the galvanometer shows zero deflection. What is the value of $R$ in $\Omega$?

Calculate the net resistance of the circuit between $A$ and $B$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module