In the following equation representing $\beta^{-}$ decay,the number of neutrons in the nucleus $X$ is ${ }_{83}^{210} Bi \longrightarrow X + { }_{-1}^{0} e + \bar{\nu}$

  • A
    $126$
  • B
    $127$
  • C
    $125$
  • D
    $84$

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