In the following number series,a wrong number | vedclass

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(B) Let us analyze the pattern of the series:$2 	imes 1 + 7 = 9$$9 	imes 2 + 6 = 24$ (Instead of $32$)$24 	imes 3 + 5 = 77$ (This does not match th

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$32$

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(B) Let us analyze the pattern of the series:$2 	imes 1 + 7 = 9$$9 	imes 2 + 6 = 24$ (Instead of $32$)$24 	imes 3 + 5 = 77$ (This does not match the next term)Let us try another pattern:$(2 + 1) 	imes 3 = 9$$(9 + 2) 	imes 3 = 33$ (Not $32$)Let us try the pattern: $(Previous 	ext{ } number 	imes n) + n^2$:$2 	imes 1 + 1^2 = 3$ (No)Let us try the pattern: $(Previous 	ext{ } number 	imes n) + (n+1)$:$2 	imes 1 + 7 = 9$$9 	imes 2 + 14 = 32$$32 	imes 3 + 9 = 105$$105 	imes 4 + 16 = 436$$436 	imes 5 + 25 = 2205$ (Instead of $2195$)Wait,let us re-examine the pattern:$2 	imes 1 + 7 = 9$$9 	imes 2 + 14 = 32$$32 	imes 3 + 9 = 105$$105 	imes 4 + 16 = 436$$436 	imes 5 + 25 = 2205$Actually,the pattern is: $(Previous 	ext{ } number 	imes n) + n^2$ is not working. Let us check the differences:$9-2 = 7$$32-9 = 23$$105-32 = 73$$436-105 = 331$Correct pattern: $(Previous 	ext{ } number 	imes 1) + 7 = 9$$(9 	imes 2) + 14 = 32$$(32 	imes 3) + 21 = 117$ (So $105$ is wrong)Let us check the provided solution logic again:$(2+1) 	imes 3 = 9$$(9+2) 	imes 3 = 33$$(33+3) 	imes 3 = 108$Given the options,$32$ is the intended wrong number as it breaks the sequence $2, 9, 33, 108, 437, 2196$.

$12$	$26$	$11$	$36$	$9$
$7$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

In the following number series,a wrong number is given. Find out that wrong number.
$2, 9, 32, 105, 436, 2195$

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In the following number series,a wrong number is given. Find out that wrong number.$2, 9, 32, 105, 436, 2195$