In the following reaction,P gives two product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is an ozonolysis of an alkene $P$ $(M.wt. = 210)$.Number of moles of $P = \frac{420 	imes 10^{-3} \,g}{210 \,g/mol} = 2 	imes 10^{-

Vedclass · Accepted Answer

$84.8$

Vedclass · Answer

(C) The reaction is an ozonolysis of an alkene $P$ $(M.wt. = 210)$.Number of moles of $P = \frac{420 	imes 10^{-3} \,g}{210 \,g/mol} = 2 	imes 10^{-3} \,mol$.Since the yield of both $Q$ and $R$ is $40 \,\%$,the number of moles of $Q$ and $R$ produced is $40 \,\%$ of $2 	imes 10^{-3} \,mol = 8 	imes 10^{-4} \,mol$.Product $Q$ is benzaldehyde ($C_6H_5CHO$,$M = 106$) and $R$ is $3$-methoxybenzaldehyde ($CH_3OC_6H_4CHO$,$M = 136$).Mass of $R = 	ext{moles} 	imes 	ext{molar mass} = 8 	imes 10^{-4} \,mol 	imes 136 \,g/mol = 1088 	imes 10^{-4} \,g = 108.8 \,mg$.Mass of $Q = 8 	imes 10^{-4} \,mol 	imes 106 \,g/mol = 848 	imes 10^{-4} \,g = 84.8 \,mg$.Given that $108.8 \,mg$ of $Q$ is produced,$R$ must be the product with mass $84.8 \,mg$.

In the following reaction,$P$ gives two products $Q$ and $R$ each in $40 \,\%$ yield. If the reaction is carried out with $420 \,mg$ of $P$,the reaction yields $108.8 \,mg$ of $Q$. The amount of $R$ produced in the reaction is closest to $....\, mg$.

Similar Questions

What is the product formed when one molecule of $HBr$ reacts with one molecule of $1,3$-butadiene at $40^{\circ}C$?

Which of the following is the most stable alkene?

Propane is obtained from propene by which method?

Consider the following reactions:
$Ph-CH_2-CH=CH_2 \xrightarrow{H^+/H_2O} P$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) NaBD_4]{(i) Hg(OAc)_2, H_2O} Q$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) H_2O_2/OH^-]{(i) BD_3, THF} R$
Identify the products $P, Q$ and $R$.

Glycol on treatment with $PI_3$ mainly gives -

Vedclass Test Series

Exam Paper Generator

Online Exam Module