In the following reaction '$X$' is
$CH_3(CH_2)_4CH_3 \xrightarrow[HCl, \Delta]{\text{Anhy. } AlCl_3} X$

  • A
    $CH_3CH_2CH_2CH_2CH_2CH_3$ ($n$-hexane)
  • B
    $CH_3CH_2CH_2CH_2CH_2Cl$
  • C
    $CH_3CH(CH_3)CH_2CH_2CH_3$ ($2$-methylpentane)
  • D
    $CH_3CH_2CH(CH_3)CH_2CH_3$ ($3$-methylpentane)

Explore More

Similar Questions

The tetraethyl lead mixed in petrol works as

$CH_3-CH_2-CH_2-CH_3 \xrightarrow[HBr]{AlCl_3}$ Product in the above reaction is:

$A$ hydrocarbon $C_{5}H_{10}$ does not react with chlorine in the dark but gives a single monochloro compound $C_{5}H_{9}Cl$ in bright sunlight. Identify the hydrocarbon.

How do you account for the formation of ethane during the chlorination of methane?

$2, 3-$dimethylhexane contains tertiary,secondary,and primary carbon atoms,respectively:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo