In the following reaction,A is: | vedclass

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Question

(A) The reaction sequence is as follows:$1$. $A$ reacts with $Br_2, h
u$ to form a brominated product.$2$. Treatment with $KOH$ (alc.) causes dehydro

Vedclass · Accepted Answer

Cyclohexane

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. $A$ reacts with $Br_2, h
u$ to form a brominated product.$2$. Treatment with $KOH$ (alc.) causes dehydrohalogenation to form an alkene.$3$. Ozonolysis $(O_3, (CH_3)_2S)$ of the alkene cleaves the ring to form a dialdehyde.$4$. Intramolecular aldol condensation followed by dehydration with $NaOH (aq) + \Delta$ yields the final product,which is cyclopent$-1-$ene$-1-$carbaldehyde.$5$. Working backwards from the final product,the precursor dialdehyde is hexane$-1,6-$dial. The alkene formed after step (ii) is cyclohexene. The brominated product is bromocyclohexane. Therefore,$A$ must be cyclohexane.

In the following reaction,$A$ is:

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