In the following reaction,Ethyl alcohol (in | vedclass

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(C) When $Ethyl \ alcohol$ $(C_{2}H_{5}OH)$ is treated with $H_{2}SO_{4}$ at $413 \ K$,the reaction proceeds via an $S_{N}2$ mechanism to form $Diethy

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diethyl ether

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(C) When $Ethyl \ alcohol$ $(C_{2}H_{5}OH)$ is treated with $H_{2}SO_{4}$ at $413 \ K$,the reaction proceeds via an $S_{N}2$ mechanism to form $Diethyl \ ether$ $(C_{2}H_{5}OC_{2}H_{5})$.Step $1$: Protonation of $Ethyl \ alcohol$ to form protonated $Ethyl \ alcohol$.Step $2$: Nucleophilic attack of another molecule of $Ethyl \ alcohol$ on the protonated $Ethyl \ alcohol$ with the loss of a water molecule.Step $3$: Loss of a proton to form $Diethyl \ ether$.

In the following reaction,$Ethyl \ alcohol$ (in excess) $+$ $H^{+}$ (from $H_{2}SO_{4}$) $\xrightarrow{413 \ K}$ product,the product is

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