In the following reaction sequence,C_2H_5NH_2 | vedclass

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Question

(B) The reaction sequence is as follows:$1$. Ethyl amine $(C_2H_5NH_2)$ reacts with nitrous acid $(HNO_2)$ to form ethanol $(C_2H_5OH)$,which is compo

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$C_2H_5NH_2$

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(B) The reaction sequence is as follows:$1$. Ethyl amine $(C_2H_5NH_2)$ reacts with nitrous acid $(HNO_2)$ to form ethanol $(C_2H_5OH)$,which is compound '$A$'.$2$. Ethanol $(C_2H_5OH)$ reacts with phosphorus pentachloride $(PCl_5)$ to form ethyl chloride $(C_2H_5Cl)$,which is compound '$B$'.$3$. Ethyl chloride $(C_2H_5Cl)$ reacts with ammonia $(NH_3)$ via nucleophilic substitution to form ethyl amine $(C_2H_5NH_2)$,which is compound '$C$'.Thus,the compound '$C$' is $C_2H_5NH_2$.

In the following reaction sequence,$C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3} C$,the compound '$C$' is

Similar Questions

$A$ primary amine,$RNH_2$ can be reacted with $CH_3-X$ to get a secondary amine,$RNHCH_3$,but the disadvantage is that $3^o$ amine and quaternary ammonium salts are also obtained as side products. Can you suggest a method where $RNH_2$ forms only $2^o$ amine?

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$\xrightarrow[{ii)\,CuCl/HCl}]{{i)\,HNO_2\,(0 - 5\,^oC)}}I$ $\xrightarrow{{Sn/HCl}}II$ $\xrightarrow[{ii)\,H_3PO_2 + H_2O}]{{i)HNO_2\,(0 - 5\,^oC)\,}}III$

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