In the following reaction, the product E is | vedclass

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(C) Aldehydes lacking $\alpha-H$ atoms undergo the Cannizzaro reaction when treated with concentrated alkali $(NaOH)$. In this reaction, one part of t

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$CH_2OH-CO_2H$

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(C) Aldehydes lacking $\alpha-H$ atoms undergo the Cannizzaro reaction when treated with concentrated alkali $(NaOH)$. In this reaction, one part of the molecule is reduced to an alcohol, and the other part is oxidized to a salt of a carboxylic acid. Glyoxal $(CHO-CHO)$ lacks $\alpha-H$ atoms and undergoes an intramolecular Cannizzaro reaction. Upon treatment with $NaOH$ followed by acidification with $H^+$, one aldehyde group is reduced to a $-CH_2OH$ group, and the other is oxidized to a $-CO_2H$ group, resulting in glycolic acid $(CH_2OH-CO_2H)$.

In the following reaction, the product $E$ is

Similar Questions

Consider the following sequence of reactions:
Ketone $A$ $\xrightarrow[2. H_2O]{1. C_2H_5MgBr} B$ $\xrightarrow[- H_2O]{H_2SO_4, \text{Heat}} C$ $\xrightarrow[2. Zn, H_2O]{1. O_3} \text{Propanone} + \text{Acetaldehyde}$
The ketone $A$ is:

Which of the following is formed when benzaldehyde reacts with concentrated sodium hydroxide?

In the following sequence of reactions, compound $M$ is:
$M$ $\xrightarrow{CH_3MgBr} N + CH_4 \uparrow$ $\xrightarrow{H^+} CH_3COCH_2COCH_3$

The product obtained from the following sequence of reactions is
$CH_3-C\equiv CH$ $\xrightarrow{HgSO_4, H_2SO_4} A$ $\xrightarrow{NaBH_4} B$

The major product of the following reaction is:

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