In the following reactions,(i) CH_3-CH(CH_3)- | vedclass

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(B) In reaction $(i)$,dehydration of $3	ext{-methylbutan-}2	ext{-ol}$ occurs via a carbocation intermediate.The initially formed $2^\circ$ carbocati

Vedclass · Accepted Answer

$CH_3-C(CH_3)=CH-CH_3$ and $CH_3-C(Br)(CH_3)-CH_2-CH_3$

Vedclass · Answer

(B) In reaction $(i)$,dehydration of $3	ext{-methylbutan-}2	ext{-ol}$ occurs via a carbocation intermediate.The initially formed $2^\circ$ carbocation $CH_3-CH(CH_3)-C^+H-CH_3$ undergoes a $1,2	ext{-hydride shift}$ to form a more stable $3^\circ$ carbocation $CH_3-C^+(CH_3)-CH_2-CH_3$.Elimination of a proton from this $3^\circ$ carbocation according to Saytzeff's rule gives the major product $A$,which is $2	ext{-methylbut-}2	ext{-ene}$ $(CH_3-C(CH_3)=CH-CH_3)$.In reaction $(ii)$,Markovnikov addition of $HBr$ to $A$ in the absence of peroxide yields the major product $C$,which is $2	ext{-bromo-}2	ext{-methylbutane}$ $(CH_3-C(Br)(CH_3)-CH_2-CH_3)$.

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