(A) The reaction is: $\underline{Cr}O_2Cl_2 + 2H_2O \longrightarrow H_2CrO_4 + 2HCl$.In $H_2CrO_4$,the oxidation state of $Cr$ is $+6$.Since $Cr$ is i

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If the product is an oxyacid with an $-ic$ suffix.

(A) The reaction is: $\underline{Cr}O_2Cl_2 + 2H_2O \longrightarrow H_2CrO_4 + 2HCl$.In $H_2CrO_4$,the oxidation state of $Cr$ is $+6$.Since $Cr$ is in its highest oxidation state $(+6)$,the corresponding oxyacid is named chromic acid,which ends with the $-ic$ suffix.Therefore,the product is an oxyacid with an $-ic$ suffix.

Class 11 Chemistry p-Block Elements (Class 11)Carbon family

Difficult

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{Cr}O_2Cl_2 + 2H_2O \longrightarrow H_2CrO_4 + 2HCl$

A
If the product is an oxyacid with an $-ic$ suffix.
B
If the product is an oxyacid with an $-ous$ suffix.
C
If the products are two oxyacids,one with an $-ic$ suffix and the other with an $-ous$ suffix.
D
If the product is not an oxyacid,neither with an $-ic$ suffix nor with an $-ous$ suffix.