(A) The reaction is the hydrolysis of oleum $(H_2S_2O_7)$: $H_2S_2O_7 + H_2O \longrightarrow 2H_2SO_4$. Here,the sulfur atom in $H_2S_2O_7$ has an oxi

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If product is an oxy acid with $-ic$ suffix

(A) The reaction is the hydrolysis of oleum $(H_2S_2O_7)$: $H_2S_2O_7 + H_2O \longrightarrow 2H_2SO_4$. Here,the sulfur atom in $H_2S_2O_7$ has an oxidation state of $+6$. The product formed is sulfuric acid $(H_2SO_4)$,where sulfur also has an oxidation state of $+6$. Since the suffix for the acid with the higher oxidation state is $-ic$,the product is an oxy acid with an $-ic$ suffix.

Class 11 Chemistry p-Block Elements (Class 11)Carbon family

Difficult

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$H_2\underset{-}{S}_2O_7 + H_2O \longrightarrow 2H_2SO_4$

A
If product is an oxy acid with $-ic$ suffix
B
If product is an oxy acid with $-ous$ suffix
C
If product are two oxy acids,one with $-ic$ suffix and the other with $-ous$ suffix
D
If product is not an oxy acid,neither with $-ic$ suffix nor with $-ous$ suffix