In the following reactions,products (A) and ( | vedclass

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(A) For the reaction with hot and concentrated $NaOH$:$6 NaOH + 3 Cl_{2} \rightarrow NaClO_{3} + 5 NaCl + 3 H_{2}O$Here,$(A)$ is $NaClO_{3}$ (sodium c

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$NaClO_{3}$ and $Ca(OCl)_{2}$

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(A) For the reaction with hot and concentrated $NaOH$:$6 NaOH + 3 Cl_{2} \rightarrow NaClO_{3} + 5 NaCl + 3 H_{2}O$Here,$(A)$ is $NaClO_{3}$ (sodium chlorate).For the reaction with dry $Ca(OH)_{2}$:$2 Ca(OH)_{2} + 2 Cl_{2} \rightarrow Ca(OCl)_{2} + CaCl_{2} + 2 H_{2}O$Here,$(B)$ is $Ca(OCl)_{2}$ (calcium hypochlorite).Thus,the products $(A)$ and $(B)$ are $NaClO_{3}$ and $Ca(OCl)_{2}$ respectively.

In the following reactions,products $(A)$ and $(B)$,respectively,are:
$6 NaOH + 3 Cl_{2} \xrightarrow{\text{hot and conc.}} (A) + \text{side products}$
$2 Ca(OH)_{2} + 2 Cl_{2} \xrightarrow{\text{dry}} (B) + \text{side products}$

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In the following reactions,products $(A)$ and $(B)$,respectively,are:$6 NaOH + 3 Cl_{2} \xrightarrow{\text{hot and conc.}} (A) + \text{side products}$$2 Ca(OH)_{2} + 2 Cl_{2} \xrightarrow{\text{dry}} (B) + \text{side products}$