In the following reactions:3B_2H_6 + 6NH_3 te | vedclass

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Question

(B) From the given chemical reactions:$1$. The reaction of diborane with excess ammonia at high temperature produces inorganic benzene $(B_3N_3H_6)$,s

Vedclass · Accepted Answer

$B_3N_3H_6, B_2H_6, H_3BO_3$

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(B) From the given chemical reactions:$1$. The reaction of diborane with excess ammonia at high temperature produces inorganic benzene $(B_3N_3H_6)$,so $X = B_3N_3H_6$.$2$. The reaction of sodium hydride with boron trifluoride produces diborane $(B_2H_6)$,so $Y = B_2H_6$.$3$. The hydrolysis of diborane produces orthoboric acid $(H_3BO_3)$,so $Z = H_3BO_3$.Therefore,the correct sequence is $X = B_3N_3H_6, Y = B_2H_6, Z = H_3BO_3$.Hence,option $(b)$ is correct.

In the following reactions:
$3B_2H_6 + 6NH_3 \text{ (excess)} \xrightarrow{\Delta} 2B_3N_3H_6 + 12H_2$
$6NaH + 2BF_3 \xrightarrow{450 \ K} B_2H_6 + 6NaF$
$B_2H_6 + 6H_2O \longrightarrow 2H_3BO_3 + 6H_2$
$X, Y$ and $Z$ are respectively:

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In the following reactions:$3B_2H_6 + 6NH_3 \text{ (excess)} \xrightarrow{\Delta} 2B_3N_3H_6 + 12H_2$$6NaH + 2BF_3 \xrightarrow{450 \ K} B_2H_6 + 6NaF$$B_2H_6 + 6H_2O \longrightarrow 2H_3BO_3 + 6H_2$$X, Y$ and $Z$ are respectively: