In the following sequence of reactions,what i | vedclass

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(C) The reaction sequence is as follows:$1$. $Toluene$ undergoes oxidation to form benzoic acid $(A)$: $C_6H_5CH_3 \xrightarrow{[O]} C_6H_5COOH$.$2$.

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Phenyl isocyanate

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(C) The reaction sequence is as follows:$1$. $Toluene$ undergoes oxidation to form benzoic acid $(A)$: $C_6H_5CH_3 \xrightarrow{[O]} C_6H_5COOH$.$2$. Benzoic acid reacts with $SOCl_2$ to form benzoyl chloride $(B)$: $C_6H_5COOH \xrightarrow{SOCl_2} C_6H_5COCl$.$3$. Benzoyl chloride reacts with $NaN_3$ to form benzoyl azide $(C)$: $C_6H_5COCl \xrightarrow{NaN_3} C_6H_5CON_3$.$4$. Upon heating,benzoyl azide undergoes Curtius rearrangement to form phenyl isocyanate $(D)$: $C_6H_5CON_3 \xrightarrow{	ext{Heat}} C_6H_5NCO + N_2$.Therefore,$D$ is phenyl isocyanate.

In the following sequence of reactions,what is $D$?
$Toluene$ $\xrightarrow{[O]} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{NaN_3} C$ $\xrightarrow{\text{Heat}} D$

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In the following sequence of reactions,what is $D$?$Toluene$ $\xrightarrow{[O]} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{NaN_3} C$ $\xrightarrow{\text{Heat}} D$