In the following sequence of reactions,
$CH_3CH_2CH_2Br$ $\xrightarrow{KOH(alc.)}$ $(A)$ $\xrightarrow{HBr}$ $(B)$ $\xrightarrow{KOH(aq.)}$ $(C)$
The product $(C)$ is

  • A
    Propene
  • B
    Propyne
  • C
    Propan$-1-$ol
  • D
    Propan$-2-$ol

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