In the following sequence of reactions,the P | vedclass

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(A) $1$. The reaction of chlorocyclopentane with $Mg$ in the presence of dry ether forms the Grignard reagent,cyclopentylmagnesium chloride $([A])$.$2

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Cyclopentane

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(A) $1$. The reaction of chlorocyclopentane with $Mg$ in the presence of dry ether forms the Grignard reagent,cyclopentylmagnesium chloride $([A])$.$2$. Grignard reagents are strong bases. When they react with a proton source like ethanol $(C_2H_5OH)$,an acid-base reaction occurs.$3$. The cyclopentyl carbanion abstracts a proton from the hydroxyl group of ethanol to form cyclopentane as the major product $(P)$.$4$. The reaction is: $C_5H_9MgCl + C_2H_5OH \rightarrow C_5H_{10} + C_2H_5OMgCl$.

In the following sequence of reactions,the $P$ is:

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