In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$n = \ldots \ldots \ldots$
- Alower limit of the median class
- Bclass length
- Ctotal frequency
- Dfrequency of the median class
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Similar Questions
The mean of the following frequency distribution is $52$. Find the missing frequency $f$.
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $5$ $3$ $4$ $f$ $2$ $6$ $13$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $5$ | $3$ | $4$ | $f$ | $2$ | $6$ | $13$ |
Medium
View SolutionFor a given frequency distribution,$n=200$,$\Sigma f_{i} d_{i}=0$ and $A=25$. Then,$\bar{x}=\ldots \ldots \ldots \ldots$
Easy
View SolutionFind the median of the following frequency distribution:
Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$ Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$
| Class | $65-85$ | $85-105$ | $105-125$ | $125-145$ | $145-165$ | $165-185$ | $185-205$ |
| Frequency | $4$ | $5$ | $13$ | $20$ | $14$ | $8$ | $4$ |
Medium
View SolutionFind the mode of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $6$ $8$ $17$ $24$ $42$ $30$ $15$ $8$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
|---|---|---|---|---|---|---|---|---|
| Frequency | $6$ | $8$ | $17$ | $24$ | $42$ | $30$ | $15$ | $8$ |
Medium
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{0} = \ldots \ldots \ldots$
Easy
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