In the given A.C. circuit,the instantaneous c | vedclass

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(C) In the given circuit,the resistor $R$ is in series with a parallel combination of the inductor $L$ and the capacitor $C$.The current flowing throu

Vedclass · Accepted Answer

$0.4 \,A$

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(C) In the given circuit,the resistor $R$ is in series with a parallel combination of the inductor $L$ and the capacitor $C$.The current flowing through the resistor $I_R$ is the total current supplied by the source.In a parallel $LC$ circuit,the currents through the inductor $(i_L)$ and the capacitor $(i_C)$ are $180^{\circ}$ out of phase with each other.Therefore,the net current through the parallel $LC$ combination is given by the difference between the magnitudes of the currents through the inductor and the capacitor:$I_{LC} = |i_L - i_C|$Given $i_L = 0.8 \,A$ and $i_C = 0.4 \,A$:$I_{LC} = |0.8 \,A - 0.4 \,A| = 0.4 \,A$Since the resistor is in series with this parallel combination,the current through the resistor $I_R$ must be equal to the net current flowing through the $LC$ branch.Thus,$I_R = 0.4 \,A$.Therefore,the correct option is $C$.

In the given $A.C.$ circuit,the instantaneous currents through the inductor and capacitor are $0.8 \,A$ and $0.4 \,A$ respectively. The instantaneous current through the resistor is:

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