In the given circuit, the values of currents | vedclass

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(C) Applying Kirchhoff's Current Law $(KCL)$ at the nodes:$1$. At the first junction: The incoming current is $5 	ext{ A}$ and one outgoing branch is

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$4 	ext{ A}, 2.5 	ext{ A}$ and $1 	ext{ A}$

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(C) Applying Kirchhoff's Current Law $(KCL)$ at the nodes:$1$. At the first junction: The incoming current is $5 	ext{ A}$ and one outgoing branch is $1 	ext{ A}$. Thus, the current entering the next part of the circuit is $I_1 = 5 	ext{ A} - 1 	ext{ A} = 4 	ext{ A}$.$2$. At the second junction: The incoming current is $I_1 = 4 	ext{ A}$. Outgoing currents are $1.5 	ext{ A}$ and $I_2$. Thus, $4 	ext{ A} = 1.5 	ext{ A} + I_2$, which gives $I_2 = 2.5 	ext{ A}$.$3$. At the third junction: The incoming current is $I_2 = 2.5 	ext{ A}$. Outgoing currents are $1.5 	ext{ A}$ and $I_3$. Thus, $2.5 	ext{ A} = 1.5 	ext{ A} + I_3$, which gives $I_3 = 1 	ext{ A}$.Therefore, the values are $I_1 = 4 	ext{ A}$, $I_2 = 2.5 	ext{ A}$, and $I_3 = 1 	ext{ A}$.

In the given circuit, the values of currents $I_1$, $I_2$ and $I_3$ respectively are:

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