In the given circuit, if the power rating of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(NONE) The voltage drop across the series resistor $R_s$ is given by:
$V_s = V_{in} - V_z = 8 \, V - 5 \, V = 3 \, V$
The current through the load r

Vedclass · Accepted Answer

$0.6 \, k \Omega$

Vedclass · Answer

(NONE) The voltage drop across the series resistor $R_s$ is given by:
$V_s = V_{in} - V_z = 8 \, V - 5 \, V = 3 \, V$
The current through the load resistor $R_L$ is:
$I_L = \frac{V_z}{R_L} = \frac{5 \, V}{1 	imes 10^3 \, \Omega} = 5 \, mA$
The maximum current through the Zener diode is determined by its power rating $P_z = 10 \, mW$:
$I_{z,max} = \frac{P_z}{V_z} = \frac{10 \, mW}{5 \, V} = 2 \, mA$
For the Zener diode to regulate, the current through the series resistor $I_s$ must be sufficient to supply the load current and the Zener current. The total current $I_s$ is $I_L + I_z$.
To find the required $R_s$, we use the condition $I_{s} = I_L + I_z$.
For the circuit to function as a regulator, the current through the Zener diode must be between $0$ and $I_{z,max}$.
Thus, $I_{s,min} = I_L + 0 = 5 \, mA$ and $I_{s,max} = I_L + I_{z,max} = 5 \, mA + 2 \, mA = 7 \, mA$.
The resistance $R_s$ must satisfy:
$R_{s,min} = \frac{V_s}{I_{s,max}} = \frac{3 \, V}{7 \, mA} = \frac{3}{7} \, k \Omega \approx 0.43 \, k \Omega$
$R_{s,max} = \frac{V_s}{I_{s,min}} = \frac{3 \, V}{5 \, mA} = 0.6 \, k \Omega$
Given the options, none match the calculated range exactly, but $R_s$ must be chosen to ensure the Zener diode operates within its limits. Typically, such questions look for a value within the range or a specific design constraint.

In the given circuit, if the power rating of the Zener diode is $10 \, mW$, the value of series resistance $R_s$ to regulate the input unregulated supply is:

Similar Questions

Consider the following statements $(A)$ and $(B)$ and identify the correct answer.
$(A)$ $A$ Zener diode is connected in reverse bias when used as a voltage regulator.
$(B)$ The potential barrier of a $p-n$ junction typically lies between $0.1 \, V$ to $0.3 \, V$.

$A$ Zener diode is connected to a battery and a load as shown below. The currents $I$,$I_Z$,and $I_L$ are respectively:

An experiment is performed to determine the $I-V$ characteristics of a Zener diode,which has a protective resistance of $R = 100 \,\Omega$ and a maximum power dissipation rating of $P = 1 \,W$. The minimum voltage range of the $DC$ source in the circuit is

When a Zener diode is used as a regulator with a Zener voltage of $10 \, V$, nearly five times the load current passes through the Zener diode. What should be the series resistance for the Zener diode if the load resistance is $2 \, k\Omega$ and the unregulated voltage supplied is $16 \, V$?

The Zener diode is used for

Vedclass Test Series

Exam Paper Generator

Online Exam Module