In the given circuit,the potential difference across the $5 \mu F$ capacitor is: (in $V$)

  • A
    $48$
  • B
    $24$
  • C
    $63$
  • D
    $21$

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If there are three capacitors and a source with $e.m.f. \ V$,how should the three capacitors be connected to the source to maximize the stored energy?

What is the equivalent capacitance between $A$ and $B$?

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Three capacitors of values $6\, \mu F, 3\, \mu F$ and $9\, \mu F$ are connected as shown in the figure. This combination is connected to a $10\, V$ battery. What is the potential difference across the plates of the $9\, \mu F$ capacitor in $V$?

$A$ parallel combination of two capacitors of capacities $2C$ and $C$ is connected across a $5 \text{ V}$ battery. When they are fully charged,the charges and energies stored in them are $Q_1, Q_2$ and $E_1, E_2$ respectively. Then $\frac{E_1-E_2}{Q_1-Q_2}$ in $\text{J/C}$ is (capacity is in Farad,charge in Coulomb and energy in $\text{J}$)

The figure shows a network of five capacitors connected to a supply voltage '$V$'. The equivalent capacitance and the energy stored in the network are respectively:

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