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(B) In an $LCR$ series circuit,the voltage across the inductor $V_L$ and the capacitor $V_C$ are in opposite phases.Given $V_1 = V_L = 300 \, V$ and $

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$220 \, V, 2.2 \, A$

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(B) In an $LCR$ series circuit,the voltage across the inductor $V_L$ and the capacitor $V_C$ are in opposite phases.Given $V_1 = V_L = 300 \, V$ and $V_2 = V_C = 300 \, V$.Since $V_L = V_C$,the circuit is in a state of resonance.In resonance,the net voltage across the $LC$ combination is $V_{LC} = V_L - V_C = 300 - 300 = 0 \, V$.The total applied voltage $V$ is equal to the voltage across the resistor $V_R$.Therefore,$V_3 = V_R = V = 220 \, V$.The current in the circuit is given by $I = \frac{V_R}{R} = \frac{220 \, V}{100 \, \Omega} = 2.2 \, A$.Thus,the reading of voltmeter $V_3$ is $220 \, V$ and the reading of ammeter $A$ is $2.2 \, A$.

In the given circuit,the readings of voltmeters $V_1$ and $V_2$ are $300 \, V$ each. The readings of voltmeter $V_3$ and ammeter $A$ are respectively:

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