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(C) In an $LCR$ series circuit,the voltage across the inductor $V_L$ and the capacitor $V_C$ are $180^{\circ}$ out of phase.Given $V_1 = V_L = 300 \,

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$220 \, V, 2.2 \, A$

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(C) In an $LCR$ series circuit,the voltage across the inductor $V_L$ and the capacitor $V_C$ are $180^{\circ}$ out of phase.Given $V_1 = V_L = 300 \, V$ and $V_2 = V_C = 300 \, V$.The net voltage across the $LC$ combination is $V_{LC} = |V_L - V_C| = |300 - 300| = 0 \, V$.The total supply voltage $V$ is given by $V = \sqrt{V_R^2 + (V_L - V_C)^2}$.Since $V = 220 \, V$ and $(V_L - V_C) = 0$,we have $V = V_R = 220 \, V$.Thus,the reading of voltmeter $V_3$ (which measures voltage across resistor $R$) is $V_3 = 220 \, V$.The current $I$ in the circuit is given by $I = \frac{V_R}{R} = \frac{220 \, V}{100 \, \Omega} = 2.2 \, A$.Therefore,the reading of ammeter $A$ is $2.2 \, A$.

In the given circuit,the readings of voltmeters $V_1$ and $V_2$ are $300 \, V$ each. The readings of the voltmeter $V_3$ and ammeter $A$ are respectively:

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