In the given figure,the equivalent resistance | vedclass

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(B) From the circuit diagram,we can observe that resistors $R_2$ and $R_3$ are connected in parallel.The equivalent resistance of this parallel combin

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$6$

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(B) From the circuit diagram,we can observe that resistors $R_2$ and $R_3$ are connected in parallel.The equivalent resistance of this parallel combination $(R_p)$ is given by:$\frac{1}{R_p} = \frac{1}{R_2} + \frac{1}{R_3} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2}$So,$R_p = 2 \,\Omega$.Now,this parallel combination is in series with resistors $R_1$ and $R_4$.The total equivalent resistance $(R_{AB})$ between points $A$ and $B$ is:$R_{AB} = R_1 + R_p + R_4$$R_{AB} = 2 + 2 + 2 = 6 \,\Omega$.

In the given figure,the equivalent resistance between the points $A$ and $B$ is ............ $\Omega$.

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