In the given figure,find the charge on the capacitor of capacitance $C$.

Find the ratio of energy stored in $5\,\mu F$ and $4\,\mu F$ capacitor in the given circuit in steady state.

The electric field between the two parallel plates of a capacitor of $1.5 \mu F$ capacitance drops to one third of its initial value in $6.6 \mu s$ when the plates are connected by a thin wire. The resistance of this wire is . . . . . . . $\Omega$. (Given,$\log_{e} 3 = 1.1$)

The circuit shown in the figure consists of a battery of $emf$ $\varepsilon = 10 \,V$,a capacitor of capacitance $C = 1.0 \, \mu F$,and three resistors of values $R_1 = 2 \, \Omega$,$R_2 = 2 \, \Omega$,and $R_3 = 1 \, \Omega$. Initially,the capacitor is completely uncharged and the switch $S$ is open. The switch $S$ is closed at $t = 0$.

In the transient circuit shown,the time constant of the circuit is:

At $t = 0$,switch $S$ is closed. The charge on the capacitor is varying with time $t$ as $Q = Q_0(1 - e^{-\alpha t})$. Find the value of $Q_0$.