In the given network, the potential differenc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The circuit consists of two parallel branches connected between points $A$ and $C$. The total current $I = 4 \, A$ enters at $A$.Branch $1$ (upper

Vedclass · Accepted Answer

$-\frac{10}{3} \, V$

Vedclass · Answer

(A) The circuit consists of two parallel branches connected between points $A$ and $C$. The total current $I = 4 \, A$ enters at $A$.Branch $1$ (upper) has resistors $2 \, \Omega$ and $3 \, \Omega$ in series, so $R_1 = 2 + 3 = 5 \, \Omega$.Branch $2$ (lower) has resistors $5 \, \Omega$ and $20 \, \Omega$ in series, so $R_2 = 5 + 20 = 25 \, \Omega$.The current $I_1$ in the upper branch is $I_1 = I \cdot \frac{R_2}{R_1 + R_2} = 4 \cdot \frac{25}{5 + 25} = 4 \cdot \frac{25}{30} = \frac{10}{3} \, A$.The current $I_2$ in the lower branch is $I_2 = I \cdot \frac{R_1}{R_1 + R_2} = 4 \cdot \frac{5}{5 + 25} = 4 \cdot \frac{5}{30} = \frac{2}{3} \, A$.Let $V_A = 0 \, V$. Then $V_B = V_A - I_1 \cdot 2 = 0 - (\frac{10}{3}) \cdot 2 = -\frac{20}{3} \, V$.$V_D = V_A - I_2 \cdot 5 = 0 - (\frac{2}{3}) \cdot 5 = -\frac{10}{3} \, V$.The potential difference $V_B - V_D = -\frac{20}{3} - (-\frac{10}{3}) = -\frac{10}{3} \, V$.

In the given network, the potential difference between the points $B$ and $D$ is

Similar Questions

When a constant voltage is applied across the ends of a metallic wire,the heat produced in the wire will be doubled if:

The equivalent resistance between $A$ and $B$ is ............ $\Omega$.

Resistances $R_1$ and $R_2$ are joined in parallel and a current is passed so that the amount of heat liberated is $H_1$ and $H_2$ respectively. The ratio $\frac{H_1}{H_2}$ has the value:

In the circuit shown in the figure,the power dissipated as heat in the $6\,\Omega$ resistor is $6\,W$. What is the value of resistance $R$ in the circuit? ................ $\Omega$

$A$ current of $2\,A$ flows through a $2\,\Omega$ resistor when connected across a battery. The same battery supplies a current of $0.5\,A$ when connected across a $9\,\Omega$ resistor. The internal resistance of the battery is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module