In the given reaction x is: CH_3 - C equiv CH | vedclass

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(C) The reaction proceeds as follows:$CH_3 - C \equiv CH$ $\xrightarrow{Excess\ HCl} CH_3 - C(Cl)_2 - CH_3 (A)$ $\xrightarrow{H_2O/OH^{-}} [CH_3 - C(O

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$CH_3 - C(=O) - CH_3$

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(C) The reaction proceeds as follows:$CH_3 - C \equiv CH$ $\xrightarrow{Excess\ HCl} CH_3 - C(Cl)_2 - CH_3 (A)$ $\xrightarrow{H_2O/OH^{-}} [CH_3 - C(OH)_2 - CH_3]$ $\xrightarrow{-H_2O} CH_3 - C(=O) - CH_3 (x)$The addition of $HCl$ to propyne follows Markovnikov's rule to form $2,2-$dichloropropane $(A)$. Hydrolysis of this geminal dihalide produces an unstable geminal diol,which undergoes dehydration to form acetone $(x)$.

In the given reaction $x$ is:
$CH_3 - C \equiv CH$ $\xrightarrow{Excess\ HCl} (A)$ $\xrightarrow{H_2O/OH^{-}} (x)$

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In the given reaction $x$ is: $CH_3 - C \equiv CH$ $\xrightarrow{Excess\ HCl} (A)$ $\xrightarrow{H_2O/OH^{-}} (x)$