In the given reaction,identify (X) and (Y): | vedclass

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(A) The starting material is $4$-methylenecyclohexan-$1$-one.$1$. Reaction with $NaBH_4$:$NaBH_4$ is a selective reducing agent that reduces aldehydes

Vedclass · Accepted Answer

$CH_2=C_6H_{10}(OH)$ and $HO-CH_2-C_6H_9=O$

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(A) The starting material is $4$-methylenecyclohexan-$1$-one.$1$. Reaction with $NaBH_4$:$NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce isolated carbon-carbon double bonds. Therefore,the ketone group is reduced to a secondary alcohol,while the exocyclic double bond remains intact. Thus,$(X)$ is $4$-methylenecyclohexan-$1$-ol.$2$. Reaction with $(i) BH_3, (ii) H_2O_2/OH^-$:This is a hydroboration-oxidation reaction. Hydroboration-oxidation is a regioselective and stereospecific reaction that adds $H$ and $OH$ across a carbon-carbon double bond in an anti-Markovnikov fashion. The $BH_3$ reagent will selectively react with the exocyclic double bond,while the ketone group remains unaffected. Thus,$(Y)$ is $4$-(hydroxymethyl)cyclohexan-$1$-one.Comparing these results with the given options,the correct products are $4$-methylenecyclohexan-$1$-ol and $4$-(hydroxymethyl)cyclohexan-$1$-one,which corresponds to option $A$.

In the given reaction,identify $(X)$ and $(Y)$:

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