In the given reaction,[X] will be: | vedclass

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(C) The reaction involves the ring opening of an epoxide (cyclopentene oxide) with a nucleophile $(N_3^-)$ followed by protonation with water $(HOH)$.

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Mixture of $(A)$ and $(B)$

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(C) The reaction involves the ring opening of an epoxide (cyclopentene oxide) with a nucleophile $(N_3^-)$ followed by protonation with water $(HOH)$.This is an $S_N2$ reaction where the nucleophile attacks the less hindered carbon atom from the back side,leading to an inversion of configuration at the site of attack.Since the epoxide is symmetric (cyclopentene oxide),the attack of $N_3^-$ at either carbon atom results in the same product due to the trans-addition mechanism.The nucleophile $(N_3^-)$ attacks from the opposite side of the oxygen atom,resulting in a trans-product where the $-N_3$ and $-OH$ groups are on opposite sides of the ring.Therefore,the product is a racemic mixture of $(1R, 2R)-2-azidocyclopentan-1-ol$ and $(1S, 2S)-2-azidocyclopentan-1-ol$,which are enantiomers.Since the question asks for the product $[X]$ and the options represent specific stereoisomers,the reaction produces a racemic mixture of the trans-isomer.

List-$I$	List-$II$
$a$. Benzenediazonium chloride $\xrightarrow{Cu_2Cl_2/HCl}$ Chlorobenzene $+ N_2$	$i$. Wurtz reaction
$b$. Benzenediazonium chloride $\xrightarrow{Cu/HCl}$ Chlorobenzene $+ N_2$	$ii$. Sandmeyer reaction
$c$. $2 CH_3CH_2Cl + 2 Na \xrightarrow{Ether} C_2H_5-C_2H_5 + 2 NaCl$	$iii$. Fittig reaction
$d$. $2 C_6H_5Cl + 2 Na \xrightarrow{Ether} C_6H_5-C_6H_5 + 2 NaCl$	$iv$. Gatterman reaction

List-$I$ Name reaction	List-$II$ Product obtainable
$A.$ Swarts reaction	$I.$ Ethyl benzene
$B.$ Sandmeyer's reaction	$II.$ Ethyl iodide
$C.$ Wurtz Fittig reaction	$III.$ Cyanobenzene
$D.$ Finkelstein reaction	$IV.$ Ethyl fluoride

In the given reaction,$[X]$ will be:

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