In the given reaction,the product E is: | vedclass

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(A) The reaction proceeds in two steps:$1$. The reaction of $p$-toluidine ($4$-methylaniline) with $NaNO_2/HCl$ at $0-5^{\circ}C$ is a diazotization r

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$4$-methylbenzonitrile

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(A) The reaction proceeds in two steps:$1$. The reaction of $p$-toluidine ($4$-methylaniline) with $NaNO_2/HCl$ at $0-5^{\circ}C$ is a diazotization reaction,which forms the diazonium salt,$4$-methylbenzenediazonium chloride $(D)$.$2$. The reaction of the diazonium salt $(D)$ with $CuCN/KCN$ is a Sandmeyer reaction,where the diazonium group $(-N_2^+Cl^-)$ is replaced by a cyano group $(-CN)$ to form $4$-methylbenzonitrile $(E)$.

In the given reaction,the product $E$ is:

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