In the given reactionCH_3-CH(OTs)-CH_2-CH_2-C | vedclass

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(C) The starting material is $CH_3-CH(OTs)-CH_2-CH_2-CH(OTs)-CH_3$,which is a ditosylate.$(i)$ Treatment with one equivalent of $SH^{\ominus}$ leads t

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$2,5-$dimethyltetrahydrothiophene

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(C) The starting material is $CH_3-CH(OTs)-CH_2-CH_2-CH(OTs)-CH_3$,which is a ditosylate.$(i)$ Treatment with one equivalent of $SH^{\ominus}$ leads to the nucleophilic substitution of one $OTs$ group by $SH^{\ominus}$ to form $CH_3-CH(SH)-CH_2-CH_2-CH(OTs)-CH_3$.(ii) Treatment with $KOH$ deprotonates the $SH$ group to form a thiolate ion $(S^{\ominus})$,which then performs an intramolecular nucleophilic substitution $(S_N2)$ on the carbon bearing the remaining $OTs$ group.This cyclization forms a five-membered ring containing a sulfur atom,resulting in $2,5-dimethyltetrahydrothiophene$.

In the given reaction
$CH_3-CH(OTs)-CH_2-CH_2-CH(OTs)-CH_3$ $\xrightarrow[(ii) \ KOH]{(i) \ SH^{\ominus} (one \ equivalent)}$ $[X]$
$[X]$ will be :

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In the given reaction$CH_3-CH(OTs)-CH_2-CH_2-CH(OTs)-CH_3$ $\xrightarrow[(ii) \ KOH]{(i) \ SH^{\ominus} (one \ equivalent)}$ $[X]$$[X]$ will be :