In the neutral state,the element M consists o | vedclass

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(C) The atomic number of element $M$ is $14$,which means every neutral atom of $M$ contains $14$ protons and $14$ electrons.For the isotopes $_{14}M^{

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atoms of $M$ may contain $14, 15$ or $16$ neutrons each

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(C) The atomic number of element $M$ is $14$,which means every neutral atom of $M$ contains $14$ protons and $14$ electrons.For the isotopes $_{14}M^{28}$,$_{14}M^{29}$,and $_{14}M^{30}$,the number of neutrons is calculated as $A - Z$:For $_{14}M^{28}$: $28 - 14 = 14$ neutrons.For $_{14}M^{29}$: $29 - 14 = 15$ neutrons.For $_{14}M^{30}$: $30 - 14 = 16$ neutrons.Thus,atoms of $M$ may contain $14, 15$,or $16$ neutrons.The average atomic weight is calculated as: $\frac{(28 	imes 60) + (29 	imes 30) + (30 	imes 20)}{60 + 30 + 20} = \frac{1680 + 870 + 600}{110} = \frac{3150}{110} \approx 28.64$.Comparing the options:$A$: The atomic weight is $\approx 28.64$,which is not between $28.0$ and $28.5$. (Incorrect)$B$: Atoms contain $14$ electrons,not $24$. (Incorrect)$C$: Atoms may contain $14, 15$,or $16$ neutrons. (Correct)$D$: Atoms contain $14$ protons,not $16$. (Incorrect)

In the neutral state,the element $M$ consists of the isotopes $_{14}M^{28}$,$_{14}M^{29}$,and $_{14}M^{30}$ in the ratio $60 : 30 : 20$ respectively. Correct statements about $M$ in the natural state include that:

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