In the nuclear transmutation _4^9 Be + X long | vedclass

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Question

(A) The given nuclear reaction is $_4^9 Be + X \longrightarrow _4^8 Be + Y$.For the reaction to be balanced,the sum of atomic numbers and mass numbers

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$(A) (\gamma, n)$

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(A) The given nuclear reaction is $_4^9 Be + X \longrightarrow _4^8 Be + Y$.For the reaction to be balanced,the sum of atomic numbers and mass numbers must be conserved on both sides.Case $1$: If $X = \gamma$ (photon,$0^0\gamma$),then $_4^9 Be + _0^0\gamma \longrightarrow _4^8 Be + _0^1 n$. Here $Y = n$ (neutron).Case $2$: If $X = p$ (proton,$_1^1 p$),then $_4^9 Be + _1^1 p \longrightarrow _4^8 Be + _1^2 D$. Here $Y = D$ (deuteron).Thus,both $(A)$ and $(B)$ are valid pairs for $(X, Y)$.

In the nuclear transmutation $_4^9 Be + X \longrightarrow _4^8 Be + Y$,the pair $(X, Y)$ is (are):

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