In the preparation of compounds of Xe,Bartlet | vedclass

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Question

(C) Neil Bartlett observed that the first ionization enthalpy of $Xe$ $(1170 \ kJ \ mol^{-1})$ is very close to that of the $O_2$ molecule $(1175 \ kJ

Vedclass · Accepted Answer

Both $O_2$ and $Xe$ have almost same ionisation enthalpy.

Vedclass · Answer

(C) Neil Bartlett observed that the first ionization enthalpy of $Xe$ $(1170 \ kJ \ mol^{-1})$ is very close to that of the $O_2$ molecule $(1175 \ kJ \ mol^{-1})$.Based on this observation,he successfully prepared the first noble gas compound by reacting $Xe$ with $PtF_6$,which was previously used to oxidize $O_2$ to $O_2^+PtF_6^-$. Thus,the similarity in ionization enthalpy was the key factor.

In the preparation of compounds of $Xe$,Bartlett had taken $O^{+}_2 Pt F^{-}_6$ as a base compound. This is because

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