In the presence of a dilute base,$C_6H_5CHO$ and $CH_3CHO$ react together to give a product. The product is

  • A
    $C_6H_5CH_3$
  • B
    $C_6H_5CH_2CH_2OH$
  • C
    $C_6H_5CH_2OH$
  • D
    $C_6H_5CH=CHCHO$

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