In the reaction,SO_2 + 2H_2S longrightarrow 3 | vedclass

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(D) In the given reaction: $SO_2 + 2H_2S \longrightarrow 3S + 2H_2O$$1$. Oxidation is defined as the loss of electrons or the addition of oxygen/remov

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$H_2S$

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(D) In the given reaction: $SO_2 + 2H_2S \longrightarrow 3S + 2H_2O$$1$. Oxidation is defined as the loss of electrons or the addition of oxygen/removal of hydrogen.$2$. In $H_2S$,the oxidation state of sulfur is $-2$. In the product $S$,the oxidation state of sulfur is $0$.$3$. Since the oxidation state of sulfur increases from $-2$ to $0$,$H_2S$ is losing electrons and is therefore being oxidised to $S$.$4$. Conversely,in $SO_2$,the oxidation state of sulfur is $+4$,which decreases to $0$ in $S$,meaning $SO_2$ is reduced.Thus,the substance that is oxidised is $H_2S$.

In the reaction,$SO_2 + 2H_2S \longrightarrow 3S + 2H_2O$,the substance that is oxidised is

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