In the reaction: P + Q longrightarrow R + S,t | vedclass

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(D) For reactant $P$:Since $t_{75\%} = 2 	imes t_{50\%}$,this is a characteristic of a first-order reaction.Therefore,the order with respect to $P$ i

Vedclass · Accepted Answer

$1$

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(D) For reactant $P$:Since $t_{75\%} = 2 	imes t_{50\%}$,this is a characteristic of a first-order reaction.Therefore,the order with respect to $P$ is $1$.For reactant $Q$:The linear variation of the concentration of $Q$ with time,as shown in the figure,indicates that the rate of reaction is independent of the concentration of $Q$.Therefore,the order with respect to $Q$ is $0$.Overall order of the reaction = (Order with respect to $P$) + (Order with respect to $Q$)Overall order = $1 + 0 = 1$.Correct Option is $(D)$.

In the reaction: $P + Q \longrightarrow R + S$,the time taken for $75\%$ reaction of $P$ is twice the time taken for $50\%$ reaction of $P$. The concentration of $Q$ varies with reaction time as shown in the figure. The overall order of the reaction is:

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