In the reaction,C_6H_5COCl xrightarrow[(ii) Y | vedclass

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(A) In step $(i)$,benzoyl chloride undergoes reduction in the presence of $H_2, Pd / BaSO_4$ to give benzaldehyde.This reaction is known as the Rosenm

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$X = H_2, Pd / BaSO_4 ; Y = NaOAc, Ac_2O$

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(A) In step $(i)$,benzoyl chloride undergoes reduction in the presence of $H_2, Pd / BaSO_4$ to give benzaldehyde.This reaction is known as the Rosenmund reduction. The reagent is a selective reducing agent,which reduces acid chlorides to an aldehyde group.In step $(ii)$,benzaldehyde undergoes condensation with acetic anhydride in the presence of an alkali salt of the acid $(NaOAc)$ to give cinnamic acid $(\alpha, \beta$-unsaturated aromatic acid).This reaction is known as the Perkin reaction.

In the reaction,
$C_6H_5COCl \xrightarrow[(ii) Y]{(i) X} C_6H_5CH=CHCOOH$
$X$ and $Y$ are

Similar Questions

In the given reaction sequence,the conversion of $B$ to $C$ is known as:

The major product $X$ formed in the following reaction is:

Identify product $B$ in the following reaction: $\text{Propanone}$ $\xrightarrow{\text{Ba(OH)}_2} A$ $\xrightarrow{\Delta, -\text{H}_2\text{O}} B$

Reactant $A$ of the above reaction is
$(A)$ + $\begin{matrix} CH_2-OH \\ | \\ CH_2-OH \end{matrix}$ $\xrightarrow{\text{Pyridine}} \begin{matrix} CH_2-O \\ | \\ CH_2-O \end{matrix} > C = O$

The product formed from the following reaction sequence is :

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In the reaction,$C_6H_5COCl \xrightarrow[(ii) Y]{(i) X} C_6H_5CH=CHCOOH$$X$ and $Y$ are