In the reaction shown,the structure of the pr | vedclass

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(C) The reaction proceeds in two steps:$1$. The first step is the Hoffmann bromamide degradation of $4$-methylbenzamide using $NaOH/Br_2$,which conver

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(C) The reaction proceeds in two steps:$1$. The first step is the Hoffmann bromamide degradation of $4$-methylbenzamide using $NaOH/Br_2$,which converts the amide group $(-CONH_2)$ into a primary amine group $(-NH_2)$,yielding $p$-toluidine ($4$-methylaniline).$2$. The second step is the acylation of the resulting $p$-toluidine with benzoyl chloride $(C_6H_5COCl)$. The lone pair on the nitrogen atom of the amine attacks the carbonyl carbon of benzoyl chloride,leading to the formation of $N$-($4$-methylphenyl)benzamide as the final product $T$.

In the reaction shown,the structure of the product $T$ is:

Similar Questions

An amine on reaction with benzenesulphonyl chloride produces a compound insoluble in alkaline solution. This amine can be prepared by ammonolysis of ethyl chloride. The correct structure of the amine is:

Product $(B)$ of this reaction is

Identify $X$ and $Y$ in the following reactions:
$Nitrobenzene \xrightarrow{Zn/NH_4Cl} X$
$Nitrobenzene \xrightarrow{Zn + KOH/C_2H_5OH} Y$

Which statement is not correct?

Pure aniline is a

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