In the reaction,$2n \ R-X \xrightarrow[\text{Dry ether}]{+2n \ Na} \text{product}$. The product obtained is

• A
  $n \ \text{Alkene}$
• B
  $n \ \text{Sodium halide}$
• C
  $n \ \text{Alcohol}$
• D
  $n \ \text{Alkane}$