In the reaction,the product D is: CH_2=CH_2 x | vedclass

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(C) The reaction sequence is as follows: $1$. $CH_2=CH_2 + Br_2 \xrightarrow{CCl_4} BrCH_2-CH_2Br$ $(A)$ $2$. $BrCH_2-CH_2Br + 2KCN \rightarrow NCCH_2

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Succinic anhydride

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(C) The reaction sequence is as follows: $1$. $CH_2=CH_2 + Br_2 \xrightarrow{CCl_4} BrCH_2-CH_2Br$ $(A)$ $2$. $BrCH_2-CH_2Br + 2KCN ightarrow NCCH_2-CH_2CN + 2KBr$ $(B)$ $3$. $NCCH_2-CH_2CN + 4H_2O + 2H^{+} ightarrow HOOCCH_2-CH_2COOH + 2NH_4^{+}$ ($C$,Succinic acid) $4$. $HOOCCH_2-CH_2COOH \xrightarrow{\Delta} 	ext{Succinic anhydride} + H_2O$ $(D)$ Thus,the product $D$ is Succinic anhydride.

In the reaction,the product $D$ is:
$CH_2=CH_2$ $\xrightarrow{Br_2/CCl_4} A$ $\xrightarrow{KCN} B$ $\xrightarrow{H_3O^{+}} C$ $\xrightarrow{\Delta} D$

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In the reaction,the product $D$ is: $CH_2=CH_2$ $\xrightarrow{Br_2/CCl_4} A$ $\xrightarrow{KCN} B$ $\xrightarrow{H_3O^{+}} C$ $\xrightarrow{\Delta} D$