In the reaction sequence: CH_3-CHO xrightarro | vedclass

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(C) In the first step,the nucleophilic addition of $CN^{-}$ to the planar carbonyl group of acetaldehyde $(CH_3-CHO)$ occurs. Since the attack can hap

Vedclass · Accepted Answer

$A$ racemic mixture of $CH_3-CH(OH)-COOH$

Vedclass · Answer

(C) In the first step,the nucleophilic addition of $CN^{-}$ to the planar carbonyl group of acetaldehyde $(CH_3-CHO)$ occurs. Since the attack can happen from either side of the $sp^2$ hybridized carbon with equal probability,a racemic mixture of acetaldehyde cyanohydrin $(CH_3-CH(OH)-CN)$ is formed. In the second step,the acidic hydrolysis of the nitrile group $(-CN)$ converts it into a carboxylic acid group $(-COOH)$ without affecting the chiral center. Thus,the final product is a racemic mixture of lactic acid ($2$-hydroxypropanoic acid),which consists of both enantiomers: $CH_3-CH(OH)-COOH$ and $HOOC-CH(OH)-CH_3$. $CH_3-CHO + HCN$ $\xrightarrow{OH^{-}} CH_3-CH(OH)-CN 	ext{ (Racemic)}$ $\xrightarrow{H_2O/H^{+}, \Delta} CH_3-CH(OH)-COOH 	ext{ (Racemic)}$

In the reaction sequence: $CH_3-CHO$ $\xrightarrow{HCN, OH^{-}} (A)$ $\xrightarrow{H_2O/H^{+}, \Delta} \text{Product}$. The product will be:

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