In the reaction $CH_3COOH$ $\xrightarrow{LiAlH_4} (A)$ $\xrightarrow{I_2 + NaOH} (B)$ $\xrightarrow{Ag \text{ (Dust)}} (C)$,the final product $(C)$ is

  • A
    $C_2H_5I$
  • B
    $C_2H_5OH$
  • C
    $C_2H_2$
  • D
    $CH_3COCH_3$

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