In the relation y = a cos (omega t - kx),the | vedclass

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(C) In the given wave equation $y = a \cos (\omega t - kx)$,the argument of the trigonometric function must be dimensionless.Therefore,the dimensions

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$[M^0 L^{-1} T^0]$

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(C) In the given wave equation $y = a \cos (\omega t - kx)$,the argument of the trigonometric function must be dimensionless.Therefore,the dimensions of $kx$ must be equal to the dimensions of a dimensionless quantity (i.e.,$[M^0 L^0 T^0]$).$[kx] = [M^0 L^0 T^0]$$[k] [x] = [M^0 L^0 T^0]$Since $[x]$ represents length,its dimension is $[L]$.$[k] [L] = [M^0 L^0 T^0]$$[k] = \frac{[M^0 L^0 T^0]}{[L]} = [M^0 L^{-1} T^0]$Thus,the correct option is $C$.

In the relation $y = a \cos (\omega t - kx)$,the dimensional formula for $k$ is

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