In the resonance tube experiment,the first resonant length is $l_1$ and the second resonant length is $l_2$. Then,the third resonant length will be:

The frequency of a vibrating air column in a pipe,open at both ends,is $f_1$. When $\frac{3}{4}$ of its length is immersed in water,the frequency of the vibrating air column is $f_2$. The value of $\frac{f_1}{f_2}$ is

The fundamental frequency of an air column in a pipe closed at one end is $100 \ Hz$. If the same pipe is open at both the ends,the frequencies produced in $Hz$ are

What is the base frequency if a pipe gives notes of frequencies $425 \text{ Hz}, 255 \text{ Hz},$ and $595 \text{ Hz}$? Also,decide whether the pipe is closed at one end or open at both ends.

An air column in a pipe,which is closed at one end,will be in resonance with a vibrating body of frequency $166 \,Hz$,if the length of the air column is .... $m$. (Assume the speed of sound in air is $332 \,m/s$)

An open pipe resonates with a tuning fork of frequency $500 \ Hz$. It is observed that two successive nodes are formed at distances $16 \ cm$ and $46 \ cm$ from the open end. The speed of sound in air in the pipe is ..... $m/s$.